Australians hate those damn lazy Americans. Cx1.8+32=F.
Or.....
Add 40. Double it. Knock off a tenth and subtract the 40 you added. Very easy to do in your head.
ie. 20+40=60. Doubled = 120. Knock off 12 (one tenth) = 108. Take away that 40 you added and you're left with 68.
It also works backwards, as add 40. Divide by 1.8 then take away your added 40.
Note: double it and take away 10% is the same result as saying multiply by 1.8
@Fernapple. To divide by 5, then multiply by nine is tricky. Try it with 17 degrees.
It's much easier to double it and knock off 10%.
eg. 17 doubled is 34. Knock off 10% (3.4) and you easily get 30.6.
Furthermore ....
By adding 40 at the beginning, and taking it off again at the end, you do not need to add (or subtract) the 32.
The logic here is superbly elegant. It is based on the fact that at -40 degrees the two scales are in agreement.
@Petter 169.376 Yes I needed a bit of paper for that, but in pratice I never really need temps to fractions of degrees, and if I did it would be in a technical working situation where i would have pen and paper to hand at least. But that one is far from easy using your method, anyway, and doing five calculations, be they easier ones, when I only need three, seems an extra burden most of the time. Moreover the conventional method promotes understanding of the problem, and is easier therefore to check for errors and reverse.
@Fernapple Actually, from a coding point of view, the add 40, select multiply or divide by 1.8, subtract 40 is a beautifully simple code.
You method has to decide whether to add or subtract 32 at the beginning or the end, then select the multiply or divide by 1.8 requires basically two sets of code.
The add 40 also gives people a real understanding of maths concepts, especially the value of zero!
@Petter Yes but your method does not work in reverse, going from F to C, if just apllied mindlessly, you still have to make choices therefore, and it is much less clear why you do so.
Besides which multiply by 1.8 as opposed to double, divide by ten, deduct result, involves a multiplication by a multiple of nine, which is what you were mainly presumable trying to avoid in the first place.